list comprehension fails, while map works
Reported by Philipp Pirozhkov | December 24th, 2008 @ 02:39 PM
I'm calling erlang function, that calls reia back in the follwing way:
A = ["app","aaa","qqq"],
'Reia_module':f(A),
Reia_module:
module Reia_module
def f(a)
# this works fine:
b = a.map { |x| x.to_string() } # convert each element to string, since that's a list of lists
# this one fails:
c = [x.to_string() | x in a]
The exception is:
Reason: {function_clause,[{reia_list,to_erl,[["app","aaa","qqq"]]},
Comments and changes to this ticket
-
Philipp Pirozhkov December 24th, 2008 @ 02:41 PM
i prefer list comprehension syntax, it's far more compact when it comes to filtering, and it allows for multiple variables
-
Tony Arcieri December 24th, 2008 @ 10:00 PM
- State changed from “new” to “resolved”
You're not properly transforming the function arguments when calling the Reia function.
Try using reia:apply
Reopen this ticket if it doesn't solve the problem
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Reia a dynamic scripting language for the Erlang virtual machine (BEAM)
Philipp Pirozhkov